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Root bridge ID Because Fender thinks it should be the root bridge, it sends its MAC address, simplified in this example to 001 The root bridge's bridge priority Because Fender thinks it should be the root bridge, it sends its priority, 12 (or 0xC in hex) Bridge ID This will be Fender's MAC address, simplified to 001 Path cost Because Fender thinks it's the root, this cost is 0 (Lower costs are better) Port ID This ID is set to the port on which the information was sent Port cost This cost is set to the cost of whichever port the advertisement was sent on in this case, 100 for ports 2, 3, and 4, and 10 for port 1 Timers This is the root bridge's (in this case, Fender's) configured timers

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init_matrix(); do{ disp_matrix(); get_player_move(); done = check(); /* see if winner */ if(done!= ' ') break; /* winner!*/ get_computer_move(); done = check(); /* see if winner */ } while(done== ' '); if(done=='X') printf("You won!\n"); else printf("I won!!!!\n"); disp_matrix(); /* show final positions */ return 0; } /* Initialize the matrix */ void init_matrix(void) { int i, j; for(i=0; i<3; i++) for(j=0; j<3; j++) matrix[i][j] = } /* Get a player's move */ void get_player_move(void) { int x, y; printf("Enter X,Y coordinates for your move: "); scanf("%d%*c%d", &x, &y); x--; y--; if(matrix[x][y]!= ' '){ printf("Invalid move, try again\n"); get_player_move(); } else matrix[x][y] = 'X'; }

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The link-local address does all the hard work in IPv6 and, as long as you don t need an Internet connection, it s all you need The old concepts of static and DHCP addressing don t really make much sense in IPv6 unless you have dedicated servers (even in IPv6, servers usually still have static IP addresses) Link-local addressing takes care of all your local network needs!

Figure 19-8: The initial BPDU advertisement The other bridges (Washburn, Ibanez, and Gibson) also think they are the root bridge, so their initial BPDUs contain information proclaiming that they are the root Remember, BPDUs are sent only to each bridge's directly connected neighbors; so, after the first advertisement, Gibson and Ibanez have not heard Washburn's advertisement, and Washburn has not heard Ibanez or Gibson's advertisements To determine which bridge is the best root bridge, the bridges take the root bridge priority and root bridge MAC address from each advertisement heard and compare these to all other advertisements, including their own The priority and MAC address are combined, as shown in Figure 19-9, and the lowest total wins

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How to generate UCC/ EAN128 barcode? - CodeProject
I suggest you use Google as there is a lot of information on the topic: http://en. lmgtfy.com/?q=ucc+ean- 128 +barcode+generator[^]. —SA.

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Figure 19-9: The priority and MAC address combine to form the final root priority At Fender (we use Fender in this case because it is the only bridge that has heard all advertisements), after combining each advertised MAC address and priority for this example, we get the results shown in Table 19-2 Table 19-2: Root Bridge Advertisements Heard at Fender Advertised Root Fender Ibanez Gibson Advertised root total priority (priority plus MAC) in hex Advertised root total priority (priority plus MAC) in decimal 0xC001 49,153 0x5900 22,784 0x1F00 7936

' ';

IPv6 subnets function the same as IPv4 subnets in that systems use them to determine whether to ARP for a MAC address or send packets to a default gateway But there are two new rules you need to know:

Washburn 0xF050 61,520

The last 64 bits of an IPv6 address are generated by the NIC, leaving a maximum of 64 bits for the subnet Therefore, no subnet is ever longer than /64 The IANA passes out /32 subnets to big ISPs and end users who need large allotments ISPs and others may pass out /48 and /64 subnets to end users Therefore, the vast majority of IPv6 subnets are between /48 and /64

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/* Get a move from the computer */ void get_computer_move(void) { int i, j; for(i=0; i<3; i++){ for(j=0; j<3; j++) if(matrix[i][j]==' ') break; if(matrix[i][j]==' ') break; } if(i*j==9) { printf("draw\n"); exit(0); } else matrix[i][j] = 'O'; } /* Display the matrix on the screen */ void disp_matrix(void) { int t; for(t=0; t<3; t++) { printf(" %c | %c | %c ",matrix[t][0], matrix[t][1], matrix [t][2]); if(t!=2) printf("\n---|---|---\n"); } printf("\n"); } /* See if there is a winner */ char check(void) { int i; for(i=0; i<3; i++) /* check rows */ if(matrix[i][0]==matrix[i][1] && matrix[i][0]==matrix[i][2]) return matrix[i][0]; for(i=0; i<3; i++) /* check columns */ if(matrix[0][i]==matrix[1][i] &&

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I suggest you use Google as there is a lot of information on the topic: http://en. lmgtfy.com/?q=ucc+ ean - 128 +barcode+generator[^]. —SA.

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